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Tuesday, November 27, 2012

Mathematical Reflections 2012, Issue 5 - Problem U243

Problem:
Let f:(a,b) \longrightarrow \mathbb{R} be a differentiable function such that f'(a)=f'(b)=0 and with the
property that there is a real valued function g for which g(f'(x))=f(x) for all x in \mathbb{R}.
Prove that f is constant.

Proposed by Mihai Piticari and Sorin Radulescu.

Solution:
Since f is differentiable in (a,b) and f'(a)=f'(b)=0, f is continuous in [a,b]. By Weierstrass's Theorem there exist maximum M and minimum m in [a,b]. If these are both attained at a and b, f is constant. If one of these is not attained at a or b, then there exists c \in (a,b) such that f(c)=M or f(c)=m. Since f is differentiable f'(c)=0, so g(0)=f(c)=f(a)=f(b), which means that f is constant in (a,b).

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